Do any of your customers ever ask you how much water their unit removes? Do you wonder how much it removes?
Here is the answer:
.25 x unit cap / 1076 = # per hour / 8.34 = gal/hr
1. .25 is the latent capacity of unit when using .75 Sev. Heat Factor
2. 1076 BTU/hr heat removal required to condense 1# of water vapor to 1# liquid
3. 8.34#= weight of 1 gal of water
24,000 x .25 = 6,000/1,076 = 5.57#/8.34# = .67 gal/hr
30,000 x .25 = 7,500/1076 = 6.97#/8.34# = .84 gal/hr
36,000 x .25 = 9,000/1,076 = 8.36#/8.34# = 1.0 gal/hr
42,000 x .25 = 10,500/1,076 = 9.75#/8.34# = 1.2 gal/hr
48,000 x .25 = 12,000/1,076 = 11.15#/8.34# = 1.3 gal/hr
54,000 x .25 = 13,500/1,076 = 12.55#/8.34# = 1.5 gal/hr
60,000 x .25 = 15,000/1,076 = 13.94#/8.34# = 1.7 gal/hr
